\documentclass[12pt]{article}

\usepackage{amsmath}
\usepackage{amsfonts}
\setlength{\textwidth}{6.5in} \setlength{\textheight}{9in} \oddsidemargin = -.1 cm
\evensidemargin = -.1 cm \topmargin=-3cm


\begin{document}
\pagestyle{empty}
\vspace*{2cm}
\leftline{\bf  Math 131 - section 01 -  Precalculus Diagnostic Quiz}
\leftline{\bf  August 31,  2007}
\vspace{.2in}
\leftline{Your Name:$\underline{\qquad\qquad\qquad\qquad\qquad\qquad\qquad}$}

\vspace{.2in}
\noindent
Circle the correct answer. {\bf Show your work.}  Please turn over for problems 4,5,6.
\begin{enumerate}
\item Simplify: $\displaystyle \sqrt{15}\left(\frac{1}{\sqrt{3}}+\frac{1}{\sqrt{5}}\right)$\vspace{.1in}

A. \ $\displaystyle 2 \frac{\sqrt{15}}{\sqrt{8}}$\ \ \ \ \ B. \ $\displaystyle \frac{\sqrt{15}}{\sqrt{3}+\sqrt{5}}$ \ \ \ \ \ C. \ $1$ \ \ \ \ \ D. \ $\displaystyle \sqrt{3}+\sqrt{5}$\ \ \ \ \ E. \ $\displaystyle 2 \sqrt{3}$\vspace{1.8in}

\item Simplify: $\displaystyle \frac{12x}{3x-6} \cdot \frac{x^2-4}{2x+4}$\vspace{.1in}

A. \ $\displaystyle \frac{x^2+12x-4}{5x-2}$ \ \ \ \ \ B. \ $\displaystyle 2x$ \ \ \ \ \ C. \ $\displaystyle -\frac{4}{3}(x-1)$ \ \ \ \ \ D. \ $\displaystyle \frac{2x(x-2)}{x+2}$ \ \ \ \ \ E. \ $\displaystyle \frac{12x^3-48x}{6x^2-12}$\vspace{1.8in}

\item Simplify: $\displaystyle \left(u^{-5}v^2 \right)^3 \left(\frac{v^2}{u}\right)^{-1}$\vspace{.1in}

A. \ $u^{-16}v^8$ \ \ \ \ \ B. \ $u^{-14}v^{4}$ \ \ \ \ \ C. \ $u^{-9}v^{3}$ \ \ \ \ \ D. \ $(uv)^{-7}$ \ \ \ \ \ E. \  $u^{-4}v^{2}$\vspace{1.8in}


\newpage\vspace*{2cm}

\item If $f(x) = 5x^2-11$, what is $f(a-2)$? \vspace{2.5in}

\item Find all values of $x$ satisfying $2(x-2)>5$. \vspace{2.5in}

\item Solve for $x$:  \ \ $2x^2 - x - 6=0$ (find all solutions). 




\end{enumerate}

\end{document}
