Mathematics 133 -- Intensive Calculus
Problem Set 8 Answers
November 11, 2000
- A) For each of the following functions,
- find all critical points,
- determine the intervals on
which f(x) is increasing or decreasing,
- identify each critical point as a local maximum, local minimum, or
neither,
- determine the intervals on which y = f(x) is concave
up or down,
- determine all inflection points
- f(x) = 2x3 - 3x2 - 12x:
critical points, -1,2, increasing on (-infinity, -1) and (2,infinity),
decreasing on (-1,2), -1 is a local maximum, 2 is a local minimum,
concave down on (-infinity,1/2), concave up on (1/2,infinity), 1/2 is the
only inflection point
- f(x) = x sqrt(x2 + 1): increasing for all x, no
critical points, concave down for all x < 0, up for all x > 0,
inflection point at x = 0
- f(x) = x - 2 sin(x) for 0 < x < 3Pi: critical points:
x = Pi/3, 5Pi/3, 7Pi/3; increasing on
(Pi/3,5Pi/3), (7Pi/3,3Pi), decreasing on (0,Pi/3),(5Pi/3,7Pi/3),
Pi/3, 7Pi/3 are local minima, 5Pi/3 is a local maximum, inflection points
x = Pi, 2Pi.
- B) Find the dimensions of a rectangle with perimeter 100 m whose
area is as large as possible: Answer: square with side 25 m.
- C) Find the point on the line y = 4x+7 that is closest
to the origin. Answer: (-28/17, 7/17).
- D) A piece of wire 10 m long is cut into two pieces. The first
is bent to form a square, and the second to form an equilateral
triangle. What are the maximum and minimum total areas that can
be enclosed. Answer: Maximum when all the wire is used for
the square, minimum when 4.35 m of the wire is used for the square.
- E) A cylindrical can without a top is made to contain V cubic inches
of liquid. Find the dimensions that will minimize the cost of the can,
assuming the metal costs a constant amount per square inch. Answer:
height = radius = cuberoot(V/Pi).
- F) A conical drinking cup is made from a circular piece of paper of
radius R
by cutting out a sector and joining the edges. Find the maximum capacity
of such a cup. Answer: 2Pi R3/(9 sqrt(3))