The third exam covers Chapter 3 (excluding Section 3.9) and Sections 4.1 and 4.2. It is recommended that you go over homework problems (HW#7 - 9), your class notes and the quizzes. Many of the problems and questions we discuss in class are excellent examples of test questions. The solutions to your WebAssign problems on HW#7 - 9 can be seen by clicking "View Key" near the top of each assignment. I have also listed many, many practice problems on WebAssign titled ``Exam #3 Review Problems.''

In addition, some good review problems from the Chapter 3 and 4 Review Exercises are listed below. The odd answers are in the back of the book while the evens are listed here. The Concept-Check at the end of each chapter (before the exercises) is also a source for good questions. The exam will be designed to take roughly one hour although you will have the full 90 minutes if needed.

Exam Review Session: Sunday, Nov. 24, 8:00 - 9:30 pm in Swords 328, led by our TA Meg Norton.
Please come prepared with specific questions.

Note: You will be allowed a scientific calculator for the exam which does NOT have graphing capabilities.

Chapter 3 Review Exercises, pp. 248 - 250
Problems:   1, 2, 3, 4, 7, 9, 11, 12, 13, 15, 16, 18, 20, 21, 23, 25, 27, 28, 33, 35, 37, 41, 42, 51, 52, 65, 68 (a,b,c,e), 73

The answers to the evens are:
2.   -sin(tan x) sec^2(x)
4.   (3x + 5)/(2x + 1)^(3/2)
12.   4(arcsin 2x)/sqrt{1 - 4x^2}
16.   (y - 2x cos y)/(2 cos(2y) - x^2 sin y - x)
18.   (2 + x)/x
20.   ((ln x)^(cos x))*(cos x/(x ln x) - (sin x)*(ln(ln x)) )
28.   -sin(x) e^(cos x) - e^x sin(e^x)
42.   y = -1
52.   (a) -2, (b) -3/8, (c) 6
68.   (a) v = 3t^2 - 12, a = 6t, (b) upward: t > 2, downward: 0 < t < 2, (c) 23, (e) speeding up: t > 2, slowing down: 0 < t < 2.

Chapter 4 Review Exercises, pp. 324 - 326
Problems:   1, 2, 3, 36, 37

The answers to the evens are:
2.   f(-1) = -sqrt{2} is the absolute min and f(2/3) = 2 sqrt{3}/9 is the absolute max.
36.   Hint: Use similar triangles to relate the radius r to the height h of the amount of water at time t. Then use the formula for the volume of a cone to get V as a function of just h. Answer: dh/dt = 8/(9 Pi) cm/sec